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求弧齿锥齿轮齿面参数方程

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发表于 2012-12-7 14:54 | 显示全部楼层 |阅读模式

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求弧齿锥齿轮齿面参数方程,我自己算的结果有点点夸张!
f =(-sin(w*t*n+atan(V/H))*w*n*(H^2+V^2)^(1/2)*cos(a)*cos(w*t)-((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*cos(k))*cos(a)-ah*sin(a))*sin(w*t)*w-cos(w*t*n+atan(V/H))*w*n*(H^2+V^2)^(1/2)*sin(w*t)-(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*sin(k))*cos(w*t)*w)*(((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*cos(k))*cos(a)-ah*sin(a))*cos(w*t)-(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*sin(k))*sin(w*t)-((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i)+cos(i))*cos(k))*cos(a)-(ah-sin(i))*sin(a))*cos(w*t)+(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i)+cos(i))*sin(k))*sin(w*t))-sin(w*t*n+atan(V/H))*w*n*(H^2+V^2)^(1/2)*sin(a)*((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*cos(k))*sin(a)+ah*cos(a)-(cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i)+cos(i))*cos(k))*sin(a)-(ah-sin(i))*cos(a))+(-sin(w*t*n+atan(V/H))*w*n*(H^2+V^2)^(1/2)*cos(a)*sin(w*t)+((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*cos(k))*cos(a)-ah*sin(a))*cos(w*t)*w+cos(w*t*n+atan(V/H))*w*n*(H^2+V^2)^(1/2)*cos(w*t)-(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*sin(k))*sin(w*t)*w)*(((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*cos(k))*cos(a)-ah*sin(a))*sin(w*t)+(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i))*sin(k))*cos(w*t)-((cos(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i)+cos(i))*cos(k))*cos(a)-(ah-sin(i))*sin(a))*sin(w*t)-(sin(w*t*n+atan(V/H))*(H^2+V^2)^(1/2)+(rw+ah*tan(i)+cos(i))*sin(k))*cos(w*t))

w角速度,n运动的速度比  H  V  rw 刀盘直径  ah 刀盘上点的高度  a齿根高  b旋转角度 i 刀盘角度 k 刀盘上点的坐标点角度 y0齿坯顶端高度
如果有人有研究的话可不可以给我传份?邮箱chenxin5236987410@163.com
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